Have to create another column with this formula and filter this column:
Function hasDigitsOrNumbers(s As String) As String
Dim ch As String, ln As Long
Dim i As Long
ln = Len(s)
For i = 1 To ln
ch = Mid(s, i, 1)
If (ch >= "0" And ch <= "9") Or (ch >= "a" And ch <= "z") Or (ch >= "A" And ch <= "Z") Then
hasDigitsOrNumbers = True
Exit Function
End If
Next
hasDigitsOrNumbers = False
End Function
=hasDigitsOrNumbers(N1) and returns true if the N1 has digits or letters, otherwise returns FALSE.
Reading VBasic2008's comment I wrote a new function which is about 2.5 times faster:
Function hasDigitsOrNumbers(s As String) As String
hasDigitsOrNumbers = (s Like "*#*") Or (s Like "*[a-z]*") Or (s Like "*[A-Z]*")
End Function