Index through a generator function

Asked Mar 01 '23 at 21:30

Active Mar 01 '23 at 21:30

Viewed 54 times

Would it be possible to index through a generator function?

For example, say I have a function like this:

def foo():
    x = 9
    yield x
    yield x+1

I understand that when calling the next() method on the generator function foo(), the output would be 9 and then 10. Would it be possible to go straight to the second output; 10 ? I haven't thought of how to do this, except by indexing through the generator function which I also don't know how to do.

asked Mar 01 '23 at 21:30

dave9060 dave9060

yield only x+1 ? – sahasrara62 Mar 01 '23 at 21:36
Potentially also helpful: [Index and Slice a Generator in Python](https://stackoverflow.com/q/2322642) – SuperStormer Mar 01 '23 at 21:39
@sahasrara62 well would I be able to output that with out having to output x by it self first, without having to rearrange the yield statements to having x+1 being first and x being second? – dave9060 dave9060 Mar 01 '23 at 21:43
`secondValue = next(itertools.islice(foo(),1))` or `_,secondValue = foo()` – Alain T. Mar 02 '23 at 05:15

Index through a generator function

0 Answers0