Select first interface with yq on YAML netplan file

Question

I'm trying to select the first interface with yq (the Github mikefarah/yq version) on /etc/netplan/00-installer-config.yaml :

$ cat /etc/netplan/00-installer-config.yaml
# This is the network config written by 'subiquity'
network:
  ethernets:
    ens160:
      link-local: []
      addresses: [x.y.z.t/24]
      routes:
       - to: default
         via: x.y.z.1
    ens192:
      link-local: []
      addresses: [a.b.c.d/24]
  version: 2
$ cat /etc/netplan/00-installer-config.yaml | yq '.network.ethernets[0]'
null
$ cat /etc/netplan/00-installer-config.yaml | yq '.network.ethernets.ens*[0]'
null
null

How do I do that with yq ?

Please mention in your question, according to the [`yq` tag info](https://stackoverflow.com/tags/yq/info), that you are using / asking for a solution with [mikefarah/yq](https://github.com/mikefarah/yq) or the "Go implementation". — pmf, Feb 20 '23 at 14:28

score 1 · Answer 1 · answered Feb 20 '23 at 14:18

.network.ethernets is an object having fields with keys (not an array having items with indices). Thus, it also has no order. But you can use keys to get an array of the keys, and use the first of them to access the field:

yq '.network.ethernets | .[keys | .[0]]' etc/netplan/00-installer-config.yaml

link-local: []
addresses: [x.y.z.t/24]
routes:
  - to: default
    via: x.y.z.1

Select first interface with yq on YAML netplan file

1 Answers1