How would I split a list of tuples into chunks

Question

I have a list that looks something like this: weather_history=((year,month,day),precip,tmin,tmax)

I need to split it into one-year chunks where each chunk is a list with one years worth of data please help!

    all_years_data: List[Weather_List] = []
    
    for line,p,n,x in weather_history:
            
        year=line[0]
        day=line[2]
        month=line[1]
        precip=p
        tmin=n
        tmax=x

        if year not in all_years_data:
            all_years_data.append(year)

this is my code so far. I've tried many different things to get all of each years worth of data into one list but can't figure it out

you need something like [ [year,day,month,tmin,tmax],[ [year,day,month,tmin,tmax] ] ? List inside list ? https://stackoverflow.com/questions/18980396/building-a-list-inside-a-list-in-python — Tharanga Abeyseela, Feb 15 '23 at 01:01

score 0 · Answer 1 · answered Feb 15 '23 at 01:17

0

How about this?

A = [((1,2,3),4,5,6), ((10,20,30),40,50,60), ((100,200,300),400,500,600)]

B = [i[0][0] for i in A]

answered Feb 15 '23 at 01:17

mike-johnson

39
3

score 0 · Answer 2 · answered Feb 15 '23 at 01:54

If your data is like this:

weather_history = ((2020,6,12),30,10,40)

you can use weather_history index without for statement :

year = weather_history[0][0]
day = weather_history[0][1]
month = weather_history[0][2]
precip = weather_history[1]
tmin = weather_history[2]
tmax = weather_history[3]
if year not in all_years_data:
    all_years_data.append(year)

But if your data is like this:

weather_history = [((2020,6,12),30,10,40),((2021,6,12),30,10,40),((2022,6,12),30,10,40)]

you should loop weather_history data with for statement :

for line in weather_history:
  year = line[0][0]
  day = line[0][1]
  month = line[0][2]
  precip = line[1]
  tmin = line[2]
  tmax = line[3]
  if year not in all_years_data:
      all_years_data.append(year)

How would I split a list of tuples into chunks

2 Answers2