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One field is not showing anymore in the deserialization of the json.

It happened because our code generator is transforming the OpenApi definition into this:

@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.EXISTING_PROPERTY, property = "type", visible = true)

Before it was working because it translated into:

@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "type", visible = true)

This code is generated from an openapi: 3.0.2 yml file with SpringCodegen.

Does anyone know if I can tell in the open api definition or in the maven openApi plugin to generate the code to use: JsonTypeInfo.As.PROPERTY?

We are using Java 11

Thank you very much

Regards.

In my local test It worked with JsonTypeInfo.As.PROPERTY and JsonTypeInfo.As.EXTERNAL_PROPERTY but the code is generated with JsonTypeInfo.As.EXISTING_PROPERTY which I cannot change in the generated clases.

Victor Trapiello Fernández
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1 Answers1

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As far as I can tell, it is not possible to configure openapi generator's JsonTypeInfo generation. These definitions are hard-coded in mustache templates in openapi generator codebase.

To see how JsonTypeInfo are generated, I would suggest the following:

  • clone openapi-generator repo.
  • checkout the tag corresponding to the version of openapi generator you are using.
  • find the mustache templates. They should be under openapi-generator/modules/openapi-generator/src/main/resources/.
  • find the corresponding generator and look at typeInfoAnnotation.mustache template .

You may want to checkout other tags to find the version that generate the JsonTypeInfo you expect, if any.

Note: I could not find any reference to JsonTypeInfo.As.EXISTING_PROPERTY in openapi generator v3.0.2

iguanito
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