How do i change Python 2d array elements?

Question

new = []
curvepoints = []   
for i in range (0, 10):
    for j in range (0, 3):
        new.append(0)
        curvepoints.append(new)
    new = []

I have initialized my main array curvepoints using the above code

p = [-30, -23, -16, -9, -2, 5, 12, 19, 30]

p is my 2nd array. I am trying to initialize every 1st element of curvepoint with element of p using the below code

for i in range(0,len(p)):
    print(curvepoints[c][0])
    curvepoints[c][0]=p[i]
    c = c+1

But it is initializing abruptly as follows:

[[-16, 0, 0], [-16, 0, 0], [-16, 0, 0], [5, 0, 0], [5, 0, 0], [5, 0, 0], [30, 0, 0], [30, 0, 0], [30, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0]]

Please do let me know how I can initialize only the 1st elements with p.

Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. — FairPluto, Jan 18 '23 at 16:21

score 0 · Answer 1 · answered Jan 18 '23 at 04:33

0

p = [-30, -23, -16, -9, -2, 5, 12, 19, 30]
curvepoints = [[x, 0, 0] for x in p]

Which gives you:

[[-30, 0, 0], [-23, 0, 0], [-16, 0, 0], [-9, 0, 0], [-2, 0, 0], [5, 0, 0], [12, 0, 0], [19, 0, 0], [30, 0, 0]]

answered Jan 18 '23 at 04:33

felipe

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How do i change Python 2d array elements?

1 Answers1