Tkinter - After Second Button Click, Change Button Function to Close Window

Question

I am trying to figure out a way to change a button's text and functionality after I have clicked the Submit button a second time. In the below instance, I am trying to:

1) Change the button's text from Submit to Close after I have entered in the username/password fields for SecondName and have clicked Submit

2) Use the Close() function to close the window.

I have attempted to accomplish these two processes by using an if/else statement.

Tkinter Code

import tkinter as tk

root = tk.Tk()

user_var = tk.StringVar()
pass_var = tk.StringVar()
entries = {}


def Submit():
    user = user_var.get()
    passw = pass_var.get()
    label_text = user_label["text"]
    char = label_text.split()[0]

    entries[char] = (user, passw)
    if char == "FirstName":
        user_label["text"] = "SecondName " + user_label["text"].split()[1]
        pass_label["text"] = "SecondName " + pass_label["text"].split()[1]
    user_var.set("")
    pass_var.set("")
    print(entries)


def Close():
    root.quit()

user_label = tk.Label(root, text="FirstName Username", width=21)
user_entry = tk.Entry(root, textvariable=user_var)

pass_label = tk.Label(root, text="FirstName Password", width=21)
pass_entry = tk.Entry(root, textvariable=pass_var, show="•")

if user_entry["text"] == "SecondName":
    sub_btn = tk.Button(root, text="Close", command=Close)
else:
    sub_btn = tk.Button(root, text="Submit", command=Submit)

sub_btn.grid(row=2, column=0)

user_label.grid(row=0, column=0)
user_entry.grid(row=0, column=1)

pass_label.grid(row=1, column=0)
pass_entry.grid(row=1, column=1)

root.mainloop()

Current Result

Expected Result

When you split `user_label["text"]` it's going to return a list of two values. You're trying to get the index of a third value. — Bryan Oakley, Jan 13 '23 at 17:24
After you got that in line 23. You need to do two case statement; one for submit and one for close. You don't need to write another function. Just one function will all reduced code sizes. — toyota Supra, Jan 13 '23 at 18:55
Consider looking at the answers below to close this question — Delrius Euphoria, Jan 24 '23 at 05:36

score 1 · Answer 1 · answered Jan 13 '23 at 21:39

The main problem here is the misunderstanding of how event driven programming works. The following line of code runs ONLY when the tkinter window is initially drawn.

if user_entry["text"] == "SecondName":
    sub_btn = tk.Button(root, text="Close", command=Close)
else:
    sub_btn = tk.Button(root, text="Submit", command=Submit)

Which means user_entry["text"] is never "SecondName". Furthermore, user_entry["text"] does not do what you expect it to be doing, it returns the name of the textvariable option and not the contents of the entry widget, what you need to do is change your function to use elif:

def Submit():
    user = user_var.get()
    passw = pass_var.get()
    label_text = user_label["text"]
    char = label_text.split()[0]

    entries[char] = (user, passw)
    if char == "FirstName":
        user_label["text"] = "SecondName " + user_label["text"].split()[1]
        pass_label["text"] = "SecondName " + pass_label["text"].split()[1]
    elif char == "SecondName":
        sub_btn.config(text='Close', command=Close) # Change button if `char` is "SecondName" only

    user_var.set("")
    pass_var.set("")
    print(entries)

Side Note: To get the value inside the entry widget, you can use user_entry.get() or user_var.get()

Tkinter - After Second Button Click, Change Button Function to Close Window

1 Answers1