Exit 1 if there any output, otherwise 0

Question

I have the following line on a GitHub Action:

find kubernetes-manifests -regextype egrep -regex '.*ya?ml$' -exec kubeconform "{}" \;

Unfortunately, kubeconform doesn't return 1 or anything else on errors; it is always 0 and some message.

Is it possible to catch the output, check if it is empty, and if it is empty, exit 0; otherwise, echo the output and exit 1?

The usage examples in the documentation (https://github.com/yannh/kubeconform#Usage-examples) show the `kubeconform` binary exiting with 1 when validating an invalid manifest and exiting with 0 when validating a valid manifest. — j_b, Jan 12 '23 at 20:23
Maybe OP's problem is that `find` does not forward the exit status of `-exec ... {} \;`. Try `-exec ... {} +` or `-quit`. — Socowi, Jan 12 '23 at 20:29
@j_b, then why my GitHub action is passing when I have an invalid YAML? Is it because I'm using it on a find/exec? — Rodrigo, Jan 12 '23 at 20:29
Switch to `xargs` or this might help: [How to get the exit code of commands started by find?](https://unix.stackexchange.com/q/392970/74329) — Cyrus, Jan 12 '23 at 20:29
Instead of `find` or `xargs` bash built-ins should be sufficient: `shopt -s nullglob globstar; kubeconform **/*yaml **/*yml`. — Socowi, Jan 12 '23 at 20:31

score 1 · Accepted Answer · answered Jan 12 '23 at 20:36

1

Switch from \; to + to preserve exit code of kubeconform.

answered Jan 12 '23 at 20:36

Cyrus

1 Answers1