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I am using the following code to run a python from node. The code works fine as a separate file but when I put it in a VSCode Extension (extension.js), it says graph.py not found.

const {spawn} = require('child_process')

const child = spawn('python3', ['graph.py'])

child.stdout.on('data', (data)=>{
    console.log(`stdout: ${data}`)
})

child.stderr.on('data', (data)=>{
    console.log(`stderr: ${data}`)
})

child.on('error', (error)=> console.log(`error: ${error.message}`))

child.on('exit', (code, signal)=>{
    if(code) console.log(`Process exit with code: ${code}`)
    if(signal) console.log(`Process killed with signal: ${signal}`)
    console.log(`DONE!!`)
})

Does anyone know how to fix it? TIA.

Amina Nasrin
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1 Answers1

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Try adding this line at the top of your code:

console.log(__dirname);

It will show you from what directory your extension code is being launched from. The graph.py file is probably not present in this directory.

You can either include the full path to the graph.py in the spawn function like this:

const child = spawn('python3', ["C:/Path/To/Your/File/graph.py"])

Or add the graph.py file in the directory your extension is being launched from.

For a permanent and deliverable solution you have to find a way to bundle python sub processes in a JS VSCode extension. This is not as easy as it may sound especially if you plan to publish your extension in the marketplace but a guide is available here. Instead you may find useful this python packet which enables you to code, build and publish (using vsce) extensions made with python.

Ioannis Tsampras
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