Zstandart(zstd) - checking return

Question

Can you please explain how the "ZSTD_isError" function works?

I check the return code from ZSTD_isError to be zero:

ZSTD_cParameter cParam;

ZSTD_bounds ZSTD_bounds_ =  ZSTD_cParam_getBounds(cParam);


status_error = ZSTD_isError(ZSTD_bounds_.error);  //ZSTD_isError RETURN 1.

if (status_error != 0)
{
    Std::cout << ZSTD_getErrorName(status_error)<< std::endl; //BUT - "No error detected"

    return 1;
}

I don't understand, the ZSTD_isError function returns 1, but after calling the ZSTD_getErrorName() function - it returns that "No error detected".

Explain, please.

score 2 · Accepted Answer · answered Dec 23 '22 at 09:26

2

Usage is:

if (ZSTD_isError(ZSTD_bounds_.error))
{
    std::cout << ZSTD_getErrorName(ZSTD_bounds_.error) << std::endl;
    return 1;
}

answered Dec 23 '22 at 09:26

Jarod42

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Please tell me that this is a joke :) This is the same code :) – Serg_ Dec 23 '22 at 09:41
2

`status_error` is not the same as `ZSTD_bounds_.error` ;-) You did equivalent of `ZSTD_getErrorName(ZSTD_isError(ZSTD_bounds_.error))` – Jarod42 Dec 23 '22 at 10:25
I'm a little "blind" today, sorry :) – Serg_ Dec 23 '22 at 10:37

Zstandart(zstd) - checking return

1 Answers1