In Processing 4, how do I make a ball sprite have a random chance to bounce left or right off a platform

Question

I have a ball sprite and I need it to have a 50/50 chance to bounce off a platform sprite. Here is the code:

 bally=bally+3;
    ballx=ballx+3;
    ballx += xspd;
    bally += yspd;
    if(bally > 580 && bally <590 && ballx < mouseX+300 && ballx > mouseX-150){
      yspd*=-3;
      
    }
     else if(bally > 580 && bally <590 && ballx < mouseX+150 && ballx > mouseX){
      yspd*=+3;
      
      
    }
    if(ballx > 900){
      xspd*=-3;
    }
    if(ballx < 0){
      xspd*=+3;
    }
    if(bally < 0 && bally > 700){
      state=LOSE;
    }

This code make the ball bounce off the walls but once it bounces off the platform at the top it only bounces to the right. I need it to be a 50/50 chance to bounce either left or right. Thanks

I tried to make an else if statement before but that didn't work, along with changing the xspd variable in said else if statement.

candied_orange · Answer 1 · 2022-12-13T22:58:31.947

0

You need a source of random:

var randNum = random(0, 100);
if (randNum < 50) {
   text("Heads", 200, 200);
   direction = 1;
} else {
   text("Tails", 200, 200);
   direction = -1;
}

Use this to chose your sign. That should let chance choose your direction.

edited Dec 13 '22 at 22:58

answered Dec 13 '22 at 22:51

candied_orange

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This works great except when i set the direction = to yspd*=-1 or 1 it doesn't make the ball bounce up it instead goes through the platofrm. Which is strange because normally that makes it go up. – Reed Dec 14 '22 at 02:59
Not sure what “the platform” is. – candied_orange Dec 14 '22 at 16:05
its a sprite of a rectangle – Reed Dec 14 '22 at 23:07
Would that be the mouseX -150 0 150 300 thing? Surprised mouseY isn't involved in it. – candied_orange Dec 15 '22 at 00:14

In Processing 4, how do I make a ball sprite have a random chance to bounce left or right off a platform

1 Answers1