SPARQL how to get all triples with Individuals?

Question

I'm just getting started with SPARQL. I am not sure where the error is. I came across the error as I was testing out the reasoner.

i use Stardog as database and the reasoner is definitely on.

i have a simple model with two classes: Building and Room and with 1 individual each: building001 and room001.

I have two ObjectProperties hasLocation and isLocationOf . Both ObjectProperties are inverse to each other.

The triple: Building001 hasLocation Room001 I have predefined, the reasoner should actually recognize the triple Room001 isLocationOf Building001 itself.

I now want to output all triples that belong to individuals. So I should get the two triples just described as a result.

With the query:

select * where {
       ?subject ?property ?object.
       ?subject a owl:NamedIndividual.
       ?property a owl:ObjectProperty.
       ?object a owl:NamedIndividual.
}

I only get the triple Building001 hasLocation Room001 as result.

with the query:

select * where {
       ?subject ?property ?object
}

I get the following triples as result :

Building001 hasLocation Room001
Room001 isLocationOf Building001
Building001 rdf:type Building
Building001 rdf:type owl:Thing
Room001 rdf:type Room
Room001 rdf:type owl:Thing

How do I get all the triples that belong to individuals? without getting rdf:type in the result?

Many thanks in advance!!

`rdf:type` is not an `owl:ObjectProperty`, thus, your query is too restrictive then — UninformedUser, Dec 09 '22 at 07:22

score 0 · Answer 1 · answered Dec 08 '22 at 20:28

You can just filter out rdf:type:

SELECT * {
    ?s ?p ?o
    FILTER (?p != rdf:type)
}

You'll notice when you turn reasoning on the triples associated with your schema are not returned but the rdf:type triples are. That's because these triples are considered part of your individual assertions, not your schema.

SPARQL how to get all triples with Individuals?

1 Answers1