I try to get user input using getline fucntion. User may type chinese charactors, some backspaces and some other charactors. Then I meet an issue. What I get in program is not I typed in termial.
My code likes below:
int main(int argc, chart argv[]) {
cout << ">>";
char *cmdBuf = (char*)malloc(1024);
while(true)
{
size_t cmdLen = 1024;
ssize_t readNum = getline(&cmdBuf, &cmdLen, stdin);
if (readNum == -1 || readNum == 1)
{
cout << ">>";
continue;
}
cout << "readNum: " << readNum << ". The input is: << cmdBuf;
cout << ">>;
}
free(cmdBuf) ;
return 0;
}
Execute the program in shell and get the results below('在' is a chinese charactor):
user input: display program output: readNum: 8. The input is: display
user input: display在 program output: readNum: 11．The input is：display在
user input: display在[backspace][backspace] ----------------- The termial shows "display". program output: readNum: 9. The input is: display[a garbled character]
user input: display在[backspace][backspace][backspace] ----------------- The termial shows "displa".
program output: readNum: 8. The input is: display
From the results, '在' contains 3 charactors. However, if I type '在', I only need type 2 backspaces to clear '在' and then I will get a wrong input in C++ program.
What should I do to make sure what C++ program get from stdin is what user see in the terminal?
