PHP: Unable to extact particular files from a ZIP archive

Question

I am trying to extract files from a zip file, but its failing with following error

Warning: copy(zip://upload/myzip-file.zip#myzip-file/file_001.csv): Failed to open stream: operation failed in {code line}

My file myzip-file.zip is placed inside upload folder, my code is able to read the contents of this file, but its unable to extract file one by one (I want to extract particular files only. I also want to avoid creation of sub folder)

$zip = new ZipArchive;
    if ($zip->open($zipPath) === true) {
        for($i = 0; $i < $zip->numFiles; $i++) {
            $filename = $zip->getNameIndex($i);
            $fileinfo = pathinfo($filename);
            copy("zip://".$zipPath."#".$filename, "my-path/".$fileinfo['basename']);
        }                  
        $zip->close();                  
    }

I suspect that copy functoin is not able to understand zip:// I found this sample on net where people have achived same using copy command but its not working for me any more.

Please note

My php script is at same location as are upload and my-path (All three in same directory)
My Zip does contain an extra folder myzip-file and its confirmed by extracting the full zip contentents and this sinppet $zip->getNameIndex($i); also revealed that.

Please note you don't have to fix it, but if have any sample which is extracting one single file from zip. It will work for me.

Question: Is it true that both "upload" and "my-path" are two separate sub-directories of current directory holding the PHP file ? — Ken Lee, Nov 21 '22 at 08:47
So your files inside the zip file are contained within a folder name `myzip-file`, is that correct? — CBroe, Nov 21 '22 at 10:54
yes, checked with zip tool, also this generated path I got from `$zip->getNameIndex($i);` — PHP Avenger, Nov 21 '22 at 11:49

Ken Lee · Answer 1 · 2022-11-22T04:53:26.857

I have tested your PHP script, it will work if

using relative path (so use $zipPath="./upload/myzip-file.zip"; and "./my-path/")
my-path is writable
over the iteration, better do not process the "file" if the $filename is actually a directory
so the directory structure is like the attached picture (myzip-file.zip is placed inside the upload folder, the process.php is the PHP to do the job)

So use the following code (I tested in a linux server and it works)

<?php

$zipPath="./upload/myzip-file.zip";

$zip = new ZipArchive;
    if ($zip->open($zipPath) === true) {
        for($i = 0; $i < $zip->numFiles; $i++) {
            $filename = $zip->getNameIndex($i);
            $fileinfo = pathinfo($filename);
      
          if (substr($filename, -1) !="/"){
            copy("zip://".$zipPath."#".$filename, "./my-path/".$fileinfo['basename']);
          }
        }                  
        $zip->close();                  
    }

?>

PHP: Unable to extact particular files from a ZIP archive

1 Answers1