While experimenting with the zig syntax, I noticed the type expression of string literals is omitted in all examples. Which is totally fine, I'm not saying it shouldn't be.
const zig_string = "I am a string"; //it looks nice enough for sure and compiles fine ofcourse
However, because this type omission is a bit inconsistent* with other type declarations in zig, it can lead to beginners (like me) misinterpreting the actual type of string literals (which is fact quite rightfully complicated and 'different'). Anyway, after reading about the type of string literals being 'pointers to (utf-8 encoded) immutable (const), sentinel terminated arrays of u8 bytes' (yes?), with next to the hard coded length field, a terminator field like so: [<length>:0]. To check my own understanding, I thought it reasonable to try adding this type expression to the declaration, similar to how other arrays are conveniently declared, so with an underscore to infer the length, because who likes counting characters?
const string: *const [_:0]u8 = "jolly good"; //doesn't compile: unable to infer array size
But it didn't compile :(. After dutifully counting characters and now specifying the length of my string however, it proudly compiled :)!
const string: *const [10:0]u8 = "jolly good"; //happily compiles
Which led me to my question:
- Why is this length specification needed for string literals and not for other literals/arrays? - (And should this be so?)
- Please correct my type description of string literals if I missed an important nuance.
I'd like to know to further deepen my understanding of the way strings are handled in zig.
*although there are more cases where the zig compiler can infer the type without it