Write with OCaml Longest Common Sottosequence (Deep Search)
Consider a finite set S of strings and an integer K. Determine, if it exists, a string x of length greater than or equal to K subsequence of each string s∈S. The problem is solved by using an in-depth search.
I tried it with two strings without k, it works! this bellow is my code:
(*trasfmorm string in list char*)
let explode s =
let rec exp i l =
if i < 0 then l
else exp (i - 1) (s.[i] :: l)
in
exp (String.length s - 1) []
(*print list of strings*)
let rec print_list_strings = function
| [] -> ()
| e::l ->
print_string e;
print_string "\n";
print_list_strings l
(*print list of char*)
let rec print_list_char = function
| [] -> print_string "\n"
| e::l ->
print_char e;
print_string " ";
print_list_char l
(*between the lists tell me which one is longer*)
let longest xs ys =
if List.length xs > List.length ys then xs
else ys
(*lcs deep*)
let rec lcs a b =
match a, b with
| [], _ | _, [] -> []
| x::xs, y::ys ->
if x = y then
x :: lcs xs ys
else
longest (lcs a ys) (lcs xs b)
(* On input: "ABCBDAB", "ABCBDAB"
The LCS returned is "BDAB" *)
let a = "ABCBDAB";; let b = "ABCBDAB";;
let a = explode a;; let b = explode b;;
print_list_char (lcs a b);;
But when I start to find the solution for s strings it seems impossible. For the moment i write the code bellow:
(* function return n-elemt of a list *)
exception Nth
let rec nth n lista =
match (n, lista) with
| (_, []) -> raise Nth
| (0, t::_) -> t
| (n, t::c) -> nth (n-1) c;;
(* functione given input list of char output string *)
let rendi_stringa s =
String.of_seq (List.to_seq s)
(* delete first n-element of a string *)
let rec drop n = function
| [] -> []
| x::xs ->
if n <= 0 then x::xs
else drop (n-1) xs ;;
(*string into a char list*)
let explode s =
let rec exp i l =
if i < 0 then l
else exp (i - 1) (s.[i] :: l)
in
exp (String.length s - 1) []
(*read k-elemt and return a list*)
let rec leggi k =
if k=0 then []
else
let x = read_line() in
(x) :: leggi (k-1)
(*print element list*)
let rec print_list = function
| [] -> ()
| e::l ->
print_string e;
print_string "\n";
print_list l
(*funzione lista string esplosa--> lista di lista*)
let rec explode_list n lista =
if n = 0 then []
else
let x = List.hd lista in
[(explode x)] @ explode_list (n-1) (List.tl lista)
(*n-esima raw e m-column of matrix*)
let pos tabla n m =
let lista = (List.nth tabla n) in
List.nth lista m;;
let subset tabella n =
let rec aux solution tot = function
| [] ->
if tot > 0 then raise NotFound
else solution
| x::rest ->
print_string x;
print_string "\n";
aux (x::solution) (tot-1) rest
in
aux [] n tabella
let subset tabella n =
let rec aux solution = function
| [] ->
if List.length solution < n then raise NotFound
else solution
| x::rest -> nuova_funzione (explode x) rest n
in
aux [] n tabella
let nuova_funzione lista_char lista_string n = function
| _, [] -> print_string "non posso piu fare niente, stringhe finite\n"
| [], _ -> print_string "ho finito confronto con la lista\n"
| [] , x::lt ->
if (lcs lista_char (explode x)) > n then
else
let longest xs ys =
if List.length xs > List.length ys then xs
else ys
(*lcs profonda*)
let rec lcs a b =
match a, b with
| [], _ | _, [] -> []
| x::xs, y::ys ->
if x = y then
x :: lcs xs ys
else
longest (lcs a ys) (lcs xs b)
(**)
(*let rec lcs stringhe num = function
| []
| List.length stringhe < num -> []
| *)
(*------------------------main--------------*)
print_string "how many strings?\n";;
let m = read_int();;
print_string "please write your strings\n";;
let lista = leggi m;;
print_string "strings wrote\n";;
print_list lista;;
explode (nth 0 c);;
let a = "ABCBDAB";;
let a = explode a;;
let b = "BDCABA";;
let b = explode b;;
let c = "BADACB";;
let c = explode c;;
My idea was to use Backtracking, but i'm stuck with logical idea, I have no idea to implement it even with pseudocode!
Any idea or advise?