I have a list of strings in my program, for example:
[ 'home', 'dog', 'park', 'house', 'hotel', 'fire' ]
and I want to know which is the most first frequent letter .
for example in that string is the letter H because it is in hotel, house and home.
I tried just 2 for cycles but I didn't get the result
You could create a list of the first letters and then use the max() function to get the highest number of occurrences in it.
lst = ['home', 'dog', 'park', 'house', 'hotel', 'fire']
max([item[0] for item in lst], key=lst.count)
output
'h'
You can get the first letter of each work with a list comprehension.
Then you can use collections.Counter to find the frequency of each letter and find the maximum of the returned dictionary:
import collections
words = [ 'home', 'dog', 'park', 'house', 'hotel', 'fire' ]
first_letters = [w[0] for w in words]
f = collections.Counter(first_letters)
print(max(f, key=f.get))
Output: h
You could create a list of the first character of each string and then use python's statistics module like so:
from statistics import mode
def most_common_first_letter(words):
first_letters = []
for word in words:
first_letters.append(word[0])
return mode(first_letters)
This uses the mode function to find the most common letter in the list of first letters.
You can use Counter from collections module, for example:
from collections import Counter
list_ = ['home', 'dog', 'park', 'house', 'hotel', 'fire']
if __name__ == '__main__':
counter = Counter(word[0] for word in list_)
print(counter.most_common(1)[0][0])
Extracting first elemnt from list item & Using collections
from collections import Counter
ls= [ 'home', 'dog', 'park', 'house', 'hotel', 'fire' ]
ls = [w[0] for w in ls]
s=(Counter(ls))
print(max(s, key=s.get))
output #
h
