How can I fix the "input ==1:" on line 19 problem such that if i input "1" it must have an output of
A-C,2-C,3-C,4-C,5-C,6-C,7-C,8-C,9-C,10-C,J-C,Q-C,K-C
This is my trial and error code for this problem
from typing import List, Any
import random
def printmenu():
print("Menu")
print("1. Show first 13 cards")
print("2. Shuffle and show first 13 cards")
print("3. Play 2 card poker")
print("4. Stack the deck and show first 13 cards")
print("5. Exit")
_input: int = int(input())
return options(_input)
def options(_input: int):
suits = ['C', 'D', 'H', 'S']
value = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
deck = []
if _input == 1:
first13cards = []
if(deck == []):
for i in suits:
for j in value:
print(j+"-"+i, end=",")
elif deck != []:
deck.clear()
first13cards.clear()
for i in range(52):
deck.append(value[random.randint(0, 12)] + suits[random.randint(0, 3)])
for i in range(13):
first13cards.append(deck[i])
return printmenu()
elif _input == 2:
for i in range(13):
deck.append(value[random.randint(0, 12)] + suits[random.randint(0, 3)])
print(deck)
return printmenu()
elif _input == 3:
#play 2 cards poker
return printmenu()
elif _input == 4:
#stack the deck & show first13 cards
return printmenu()
elif _input == 5:
exit() # exit the program
for j in value:
suit = suits[random.randint(0, 3)]
_temp = j + suit + ""
deck.append(_temp)
print(deck)
return deck
if __name__ == '__main__':
while True:
printmenu()
if printmenu() == 5:
break
This is my trial and error code for this set
