How to compare Cisco software versions in Python

Question

I need to compare software versions for Cisco devices in Python, but unfortunately packaging.version doesn't support this format when 3rd and 4th indexes are joined by letters. Maybe someone knows a package that can compare the following versioning format "15.2.7E7"

from packaging.version import Version

# working
if Version("15.2.7") > Version("15.2.1"):
    print("packaging.version is working")


# not working
try:
    if Version("15.2.7E7") > Version("15.2.7E1"):
        print("Cisco version is working")
except Exception:
    print("Cisco version is not working")

# result
# packaging.version is working
# Cisco version is not working

I didn't find a solution and made package based on package.version — pyjedy, Nov 09 '22 at 21:52

score 0 · Answer 1 · answered Nov 09 '22 at 21:59

swversion package can parse and compare Cisco software versions, as in the following example

import re
from swversion import SwVersion

text = "Cisco IOS Software, C2960X Software (C2960X-UNIVERSALK9-M), Version 15.2(4)E10, ..."
text = re.search(r"Version (\S+),", text)[1]

version1 = SwVersion(text)  # 15.2(4)E10
version2 = SwVersion("15.2(4)E11")

assert version1 < version2
assert version1 <= version2
assert not version1 > version2
assert not version1 >= version2
print(version1)
print(version2)
# 15.2(4)e10
# 15.2(4)e11

How to compare Cisco software versions in Python

1 Answers1