What is the correct formula for the location of an NSRulerMarker
on a vertical NSRulerView
, if the client view is flipped?
The situation: I have a view (let's call it the "main view") that is embedded in an NSScrollView
with rulers, and it has subviews. The user can drag these subviews around, and while dragging, I want to indicate the current position on the rulers.
The main view is flipped: The zero point is top-left.
The horizontal position is pretty simple:
NSPoint scroll = myScrollView.documentVisibleRect.origin;
NSRect rect = mySubView.frame;
rulerMarkerDragLeft.markerLocation = rect.origin.x - scroll.x;
However the same method for the vertical position...
rulerMarkerDragTop.markerLocation = rect.origin.y - scroll.y;
does not work. The marker is only in the correct position when the scrollview has been scrolled down to the extreme bottom. For every n points scrolled back up, the marker location is n points too high. This is independent of the main view's size or the size of the visible area.
I can't seem to wrap my head around this problem; I guess there is a value I need to subtract from my result that expresses how far up the scrollview has been scrolled (or rather, how much further it can be scrolled down), but I don't think I can derive that value from myScrollView.documentVisibleRect
...?
I may have overlooked something simple, but I can't find the solution.
Edit 2022-11-02 17:17 CET: Found the problem. I had set the NSRulerView
s clientView
to the contentView of the window. I am now setting it to the "main view" (ie. the view inside the scroll view), and now it works "automagically": I just set the marker locations to the subviews frame
, no correction for scroll position or anything else needed.