Python raises a NameError when using a type hint in arguments of class method

Question

Take a look at this code:

class Test:
    def __eq__(self, rhs: Test):
        # ...
        pass

The code fails with the following output:

Traceback (most recent call last):
  File "test.py", line 1, in <module>
    class Test:
  File "test.py", line 2, in Test
    def __eq__(self, rhs: Test):
NameError: name 'Test' is not defined

How do I use a type hint of a class in the class method arguments itself?

@Axe319, yes, absolutely. Thanks – g00dds Nov 01 '22 at 15:44 — g00dds, Nov 01 '22 at 15:44

score 0 · Accepted Answer · answered Nov 01 '22 at 15:41

0

Because Test is not defined yet, you will need to do a forward declaration like this:

class Test:
    def __eq__(self, rhs: "Test"):
        # ...
        pass

answered Nov 01 '22 at 15:41

jprebys

2,469
1
11
16

Python raises a NameError when using a type hint in arguments of class method

1 Answers1