unit test for function in lua using busted

Question

I have a file contain multi function and I try to write unit-test for specific function using busted framework

code.lua:

function myfunc1(a,b)
-- do someting
return c1
end

function myfunc2(a2,b2)
-- do someting
return c2
end

code_spec.lua:

describe("function test", function ()
    it("test result is the same in myfunc1", function ()
        local functions = require "code"
        local result = functions.myfunc1(500, 200)
        assert.are.same(300, result)
    end)
end)

but I get error like this

code_spec.lua:4: attempt to index a boolean value (local 'functions')

I need my unit test to evaluate output for specific input in myfunc1 or myfunc2 while my code and tests are in separated files.

I test different approaches, but documentation is a little confusing or lack of good example.

score 2 · Accepted Answer · answered Oct 20 '22 at 05:33

Your code.lua pollutes the global namespace rather than returning its exports. To fix your problem, you can either adjust your test to work around that problem, or you can fix that problem. To work around the problem, you'd call myfunc1 from the global namespace, like this:

        require "code"
        local result = myfunc1(500, 200)

To fix the problem, you'd instead return an export table from code.lua, like this:

local p = {}

function p.myfunc1(a,b)
-- do someting
return c1
end

function p.myfunc2(a2,b2)
-- do someting
return c2
end

return p

In test part how should I add multiple input for example myfunc1(500, 200) than myfunc1(5, 29) etc… And then result of arrest each of them.? — JACK, Oct 20 '22 at 16:26

unit test for function in lua using busted

1 Answers1