Redirect Python Bottle stderr stdout to "logging" logger (or more generally using any WSGI server)

Question

By default, Python Bottle with WSGIRefServer logs the uncaught exceptions to stderr (and stdout for requests logging).

I'd like to log uncaught exceptions to a logging logger object. The following code with monkey-patching seems to work, but what is the standard way to do it following the official WSGI specification?

import logging, sys

logging.basicConfig(filename='test4.log', filemode='a', format='%(asctime)s %(levelname)s %(message)s', datefmt='%Y-%m-%d %H:%M:%S', level=logging.DEBUG)
log = logging.getLogger('foobar')
log.info("hello")

class LoggerWriter:
    def __init__(self, level):
        self.level = level
    def write(self, message):
        self.level(message.strip())
    def flush(self):
        pass

sys.stdout = LoggerWriter(log.info)
sys.stderr = LoggerWriter(log.error)
from bottle import route, run, template, request
@route('/')
def index():
    sqdf         # uncaught exception !!! 
    return "hhello"
run()

Notes:

• see How to redirect stdout and stderr to logger in Python

• the WSGI standard requires that logging is done through a file-like object wsgi.errors, how to redirect this to a logging logger?

• this attempt does not work:

  import logging, sys, traceback
  logging.basicConfig(filename='test.log', filemode='a', format='%(asctime)s %(levelname)s %(message)s', datefmt='%Y-%m-%d %H:%M:%S', level=logging.DEBUG)
  sys.excepthook = lambda exctype, value, tb: logging.error("", exc_info=(exctype, value, tb))
  logging.info("hello")
  from bottle import route, run, template, request
  @route('/')
  def index():
      sqdf         # uncaught exception !!! not logged 
      return "hello"
  run()