VSCode API Extension get URI of context menu

Question

I am building a VSCode-Extension and I managed to call my function via 'right-click' on the files.

This is my package.json:

  "main": "./extension.js",
  "contributes": {
    "commands": [{
      "command": "flutter-localization-generator.create",
      "title": "localize_it: create"
    }],
    "menus": {
      "explorer/context": [{
          "command": "flutter-localization-generator.create"
    }]
  }

The thing is that I need the URI from where the user clicked on the method. Is that possible? How do I access it inside the activate?

function activate(context) {

    console.log('Congratulations, your extension "flutter-localization-generator" is now active!');

    let disposable = vscode.commands.registerCommand('flutter-localization-generator.create', function () {


        console.log(context.globalStorageUri);
        console.log(context.extensionUri);

        console.log(context.extensionPath);
        console.log(context.rootPath);

    });

    context.subscriptions.push(disposable);
}

I tried different of things but all of the above logs do not get me the desired path.

score 2 · Accepted Answer · answered Oct 19 '22 at 15:49

Which file or files were selected and right-clicked will be passed to your context menu command, see more at https://stackoverflow.com/a/70307717/836330.

Add args (any name you want) to your command callback - the information you want will automatically be passed as arguments there.

let disposable = vscode.commands.registerCommand('flutter-localization-generator.create', function (...args) {

Then args will be an array containing in [0] the file that was right-clicked on, and in [1] all the files that might have been selected when one of them was right-clicked and your context menu function selected and run.

VSCode API Extension get URI of context menu

1 Answers1