GitLab CI: how to return command stdout to the code where it was called?

Asked Oct 12 '22 at 18:59

Active Oct 12 '22 at 19:48

Viewed 138 times

I have this piece of code in the yaml file:

.setUpEnvironment:
  stage: provision
  script:
    - |
      cd ansible
      ansible-playbook install_app.yml <...>
      <... n more lines here>
      echo 'rc = ' $(install_app.rc)
      echo 'stdout = ' $(install_app.stdout)
  allow_failure: true

I need to send notification if the script fails. The problem is that neither install_app.rc nor install_app.stdout works for me. There is 'bash: line 217: install_app_win.rc: command not found rc = bash: line 218: install_app_win.stdout: command not found' Do you have any ideas how to fix this behavior?

Thanks in advance, Irina

edited Oct 12 '22 at 19:48

asked Oct 12 '22 at 18:59

that_startup_girl

1

Hi that_startup_girl welcome to SO. That posted yaml sure does look like GitLab CI, and not ansible; are you sure you have tagged your question correctly? Good luck! – mdaniel Oct 12 '22 at 19:13
Thanks, @mdaniel, I'll fix the tag – that_startup_girl Oct 12 '22 at 19:47

GitLab CI: how to return command stdout to the code where it was called?

0 Answers0