The type ... must be convertible to ... in order to use it as parameter 'T' in the generic method

Question

Below I will describe my problem with a short sample code:

// model interface and implmentation
public interface IModel { }

public class Model : IModel{}

// generic interface which constraint T from IModel
public interface IBaseInterface<T> where T:IModel{ }

public interface IDerivedInterface : IBaseInterface<Model>{}


public class Test
{
    void FuncTest<T>() where T:IBaseInterface<IModel>
    {
        
    }

    void CallFunc()
    {
        // error: ... see below
        FuncTest<IDerivedInterface>();
    }
}

error info is :The type 'IDerivedClass' must be convertible to 'IBaseClass<IDerivedClass>' in order to use it as parameter 'T' in the generic method 'void Test.FuncTest<T>()'

my understanding is: Model implements the IModel interface, and IDerivedInterface implements the IBaseInterface interface,then IDerivedInterface should be able to be converted to IBaseInterface<IModel> type,but compiler tells me it cannot convert.

I have read related questions on stackoverflow such as：

1. The type must be convertible in order to use it as parameter in the generic class
2. error CS0309: The type ... must be convertible to ... in order to use it as parameter in the generic type or method
3. The type 'TNestedInterface' must be convertible to 'INestedInterfaceTest' in order to use it as parameter 'TNestedInterface'
4. Can not use parameter in generic class, because is not convertible to base class, although all constraints seem to be good
5. The type 'T' must be convertible in order to use it as parameter 'T' in the generic type or method

I guess the reason may be related to covariance and inversion, ut the answer to the question in the link above doesn't make me understand the problem, can anyone give me a clear explanation?

error info screenshot

1. ide: rider 2022.2 version
2. .Net version: .Net 6