Can't create Breeze DenseMatrix with Scala3

Question

When trying to create a dense matrix of type Option with Scala 3 I receive an error.

  val dm1 = DenseMatrix((1,2),(1,2))   // <- this works
  val dm2 = DenseMatrix((Some(1),Some(2)),(Some(1),Some(2)))  <- doesn't work

Error: no implicit argument of type breeze.storage.Zero[V] was found for parameter zero of method apply in trait MatrixConstructors

Btw, it is working in Scastie and Scala 2.

https://scastie.scala-lang.org/89HUyuXNQrqWDPNpRbtrOw

The 2nd line doesn't compile in Scala 2.13.9 either https://scastie.scala-lang.org/7bQBBfLVT6eJSQPnIffsoA — Dmytro Mitin, Oct 10 '22 at 09:58
Ok, if you look at my scastie. I create a vector and then a matrix from it. Works in Scastie but wont work in my Scala project. — Sven, Oct 10 '22 at 10:11

Dmytro Mitin · Accepted Answer · 2022-10-10T13:57:24.430

Try to add necessary implicit

implicit val optIntZero: Zero[Option[Int]] = Zero(Some(0))
implicit val someIntZero: Zero[Some[Int]] = Zero(Some(0))

or more generally

implicit def optZero[A](implicit zero: Zero[A]): Zero[Option[A]] = Zero(Some(zero.zero))
implicit def someZero[A](implicit zero: Zero[A]): Zero[Some[A]] = Zero(Some(zero.zero))

or just

implicit def someZero[F[t] >: Some[t], A](implicit zero: Zero[A]): Zero[F[A]] = Zero(Some(zero.zero))

Problem with evidence parameters in breeze

score 1 · Answer 2 · answered Oct 11 '22 at 06:37

1

Another easy approach. Create a "simple type" matrix and map to to the target type.

val v = DenseVector(1, 1, 1)
val dm1 = DenseMatrix(v,v)
val dm2 = dm1.map( Some(_))

answered Oct 11 '22 at 06:37

Sven

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Can't create Breeze DenseMatrix with Scala3

2 Answers2

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