I am reading the 3.3 Unicode Escapes section in the lang spec. (https://docs.oracle.com/javase/specs/jls/se19/html/jls-3.html#jls-3.3)
There is this particular piece of text I am having difficulty understanding:
consider how many backslashes appeared contiguously as raw input characters in the result, back to a non-backslash character or the start of the result. (It is immaterial whether any such backslash arose from an ASCII \ character in the compiler's raw input or from a Unicode escape \u005c in the compiler's raw input.) If this number is even, then the ASCII \ character is eligible to begin a Unicode escape; if the number is odd, then the ASCII \ character is not eligible to begin a Unicode escape.
For example, the raw input "
\\u2122=\u2122" results in the eleven characters " \ \ u 2 1 2 2 = ™ " because while the second ASCII \ character in the raw input is not eligible to begin a Unicode escape, the third ASCII \ character is eligible, and \u2122 is the Unicode encoding of the character ™.
but in \\u2122=\u2122, in the left side of =, there are 2 backslashes making it eligible to begin a unicode escape, but the right side of =, there's only 1 backslash.
I understand that this is wrong interpretation because it makes sense that \\u2122 is wrong. And I can count it as being odd number of backslashes if I am ignoring the backslash associated with the unicode escape. But there is this following mention in parentheses:
It is immaterial whether any such backslash arose from an ASCII \ character in the compiler's raw input or from a Unicode escape \u005c in the compiler's raw input.
I want to understand how and where my understanding of this went wrong.
