Write a c program that asks for a string and tells the frequency of all characters in the word

Asked Oct 07 '22 at 18:20

Active Oct 07 '22 at 21:12

Viewed 60 times

How do I find the frequency of all the characters and not only one character (using functions and strings)? Example input: aaaaabbccc Expected output: 'a' : 5 'b' : 2 'c' : 3

#include <stdio.h>
int main() {
    char string[1000], character;
    int amount = 0;

    printf("Enter a word: ");
    fgets(string, sizeof(string), stdin);

    printf("Enter any character from the word to find the frequency of the character: ");
    scanf("%c", &character);

    for (int i = 0; string[i] != '\0'; ++i) {
        if (character == string[i])
            ++amount;
    }

    printf("Frequency of %c = %d", character, amount);
    return 0;
}

edited Oct 07 '22 at 21:12

asked Oct 07 '22 at 18:20

2

Convert `amount` to an array is probably what you want. – Fiddling Bits Oct 07 '22 at 18:21
How do i do that? – Oct 07 '22 at 18:27
It depends on if you only care about alphabetical characters and if case matters. `amount[26]` would be simple if you only care about `'a'` to `'z'`. – Fiddling Bits Oct 07 '22 at 18:29
yes i only care about alphabetical characters. – Oct 07 '22 at 18:31
How about something like `amount[character - 'a']++`. – Fiddling Bits Oct 07 '22 at 18:32
1

as a replacement for ++amount; ? – Oct 07 '22 at 18:34
1

Of course. You need separate counts for each letter, that's what the array is for. You're only counting the one letter that the user entered. – Barmar Oct 07 '22 at 18:41

Write a c program that asks for a string and tells the frequency of all characters in the word

0 Answers0