LUA, divide negative value

Question

For example, I have vaule "a" = -23 who I want to print as -2.3

I write this code who work good when a > 0, also work in other language string_buf = string.format ( "%1d,%d" ,a //10, math.abs(a) %10) but when I use only use "//" then I have one more and instead -2.3 see to -3.3

Where is problem?.

Try `math.modf(a/10)` – Egor Skriptunoff Oct 06 '22 at 21:52 — Egor Skriptunoff, Oct 06 '22 at 21:52
or `string.format("%.1f", a/10):gsub("%.",",")` – Mike V. Oct 07 '22 at 09:20 — Mike V., Oct 07 '22 at 09:20

score 0 · Answer 1 · answered Oct 08 '22 at 15:04

0

Ok, I try modf. Works.

    a= 0xFF16   -- -234

--16bit register is negative?
if (a & 0x8000 ~=0) then 
    a=  (~a +1) & 0xFFFF
    a = -a 
end

string_buf = string.format ( "%1d,%d" ,math.modf(a/10), math.abs(a)%10)

answered Oct 08 '22 at 15:04

terefere

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LUA, divide negative value

1 Answers1