I want to be able to list the items that either a user has added (they are listed as the creator) or the item has been approved.
So I basically need to select:
item.creator = owner or item.moderated = False
How would I do this in Django? (preferably with a filter or queryset).
There is Q objects that allow to complex lookups. Example:
from django.db.models import Q
Item.objects.filter(Q(creator=owner) | Q(moderated=False))
You can use the | operator to combine querysets directly without needing Q objects:
result = Item.objects.filter(item.creator = owner) | Item.objects.filter(item.moderated = False)
(edit - I was initially unsure if this caused an extra query but @spookylukey pointed out that lazy queryset evaluation takes care of that)
It is worth to note that it's possible to add Q expressions.
For example:
from django.db.models import Q
query = Q(first_name='mark')
query.add(Q(email='mark@test.com'), Q.OR)
query.add(Q(last_name='doe'), Q.AND)
queryset = User.objects.filter(query)
This ends up with a query like :
(first_name = 'mark' or email = 'mark@test.com') and last_name = 'doe'
This way there is no need to deal with or operators, reduce's etc.
You want to make filter dynamic then you have to use Lambda like
from django.db.models import Q
brands = ['ABC','DEF' , 'GHI']
queryset = Product.objects.filter(reduce(lambda x, y: x | y, [Q(brand=item) for item in brands]))
reduce(lambda x, y: x | y, [Q(brand=item) for item in brands]) is equivalent to
Q(brand=brands[0]) | Q(brand=brands[1]) | Q(brand=brands[2]) | .....
Similar to older answers, but a bit simpler, without the lambda...
To filter these two conditions using OR:
Item.objects.filter(Q(field_a=123) | Q(field_b__in=(3, 4, 5, ))
To get the same result programmatically:
filter_kwargs = {
'field_a': 123,
'field_b__in': (3, 4, 5, ),
}
list_of_Q = [Q(**{key: val}) for key, val in filter_kwargs.items()]
Item.objects.filter(reduce(operator.or_, list_of_Q))
operator is in standard library: import operator
From docstring:
or_(a, b) -- Same as a | b.
For Python3, reduce is not a builtin any more but is still in the standard library: from functools import reduce
P.S.
Don't forget to make sure list_of_Q is not empty - reduce() will choke on empty list, it needs at least one element.
Multiple ways to do so.
1. Direct using pipe | operator.
from django.db.models import Q
Items.objects.filter(Q(field1=value) | Q(field2=value))
2. using __or__ method.
Items.objects.filter(Q(field1=value).__or__(field2=value))
3. By changing default operation. (Be careful to reset default behavior)
Q.default = Q.OR # Not recommended (Q.AND is default behaviour)
Items.objects.filter(Q(field1=value, field2=value))
Q.default = Q.AND # Reset after use.
4. By using Q class argument _connector.
logic = Q(field1=value, field2=value, field3=value, _connector=Q.OR)
Item.objects.filter(logic)
Snapshot of Q implementation
class Q(tree.Node):
"""
Encapsulate filters as objects that can then be combined logically (using
`&` and `|`).
"""
# Connection types
AND = 'AND'
OR = 'OR'
default = AND
conditional = True
def __init__(self, *args, _connector=None, _negated=False, **kwargs):
super().__init__(children=[*args, *sorted(kwargs.items())], connector=_connector, negated=_negated)
def _combine(self, other, conn):
if not(isinstance(other, Q) or getattr(other, 'conditional', False) is True):
raise TypeError(other)
if not self:
return other.copy() if hasattr(other, 'copy') else copy.copy(other)
elif isinstance(other, Q) and not other:
_, args, kwargs = self.deconstruct()
return type(self)(*args, **kwargs)
obj = type(self)()
obj.connector = conn
obj.add(self, conn)
obj.add(other, conn)
return obj
def __or__(self, other):
return self._combine(other, self.OR)
def __and__(self, other):
return self._combine(other, self.AND)
.............
Ref. Q implementation
This might be useful https://docs.djangoproject.com/en/dev/topics/db/queries/#spanning-multi-valued-relationships
Basically it sounds like they act as OR
Item.objects.filter(field_name__startswith='yourkeyword')
