I'm using Plotly in python to create multiple 3d scatter plots (plotly.express.scatter_3d)
Each one is a complete and independent px.scatter_3d fig. They are gathered in a list:
all_figs = [fig1,fig2, ... , fig6]
I want to create a single fig with a button (or buttons) that allows me to toggle between each one (one at a time)
I've tried multiple approaches with no success. My latest version is:
(1) for each fig inside all figs i've crreated a dictionary, and concatinated them to a list called all_figs_dicts
all_figs_dicts = list()
.
for selected_observation_idx, selected_observation in enumarate(obs):
#....
fig_dict = dict()
fig_dict['label'] = selected_observation
fig_dict['method'] = 'update'
visible = [False] * len(all_figs)
visible[selected_observation_idx] = True
fig_dict['args'] = [{'title': f'--> {selected_observation}', 'visible': visible}, ]
all_figs_dicts.append(fig_dict)
And then combining them as follows:
updatemenus = list([
dict(active=0,
buttons=all_figs_dicts
)
])
layout = dict(title='Yahoo', showlegend=False,
updatemenus=updatemenus)
fig = dict(data=all_figs_dicts, layout=layout)
plotly.offline.plot(fig, auto_open=True, show_link=True)
But i get an error message:
Did you mean "line"?
Bad property path:
label
^^^^^
Thanks