How do you add Java Based Spring config to an existing web.xml?

Question

I have an existing web.xml and I am trying to add springs to a project. I would like to use java based spring config: like the following.

AnnotationConfigWebApplicationContext appContext = new AnnotationConfigWebApplicationContext();
        appContext.register(AppConfig.class);

However, I don't want a WebApplicationInitializer, because I don't want to rewrite the web.xml.

Is there way to reference the AppConfig.class from the web.xml? I don't want to define all my object in xml like old spring.

Thanks

@Grim I was to modify the web.xml. I don't want to replace it. — GC_, Sep 19 '22 at 21:58

score 0 · Accepted Answer · answered Sep 19 '22 at 22:10

Using spring (without spring-boot) there is a second path used by vintage programmers of old, an anicent and a forgotten path, by defining a listener. Scolls of new recommend a 3.0 servlet-api.

<web-app xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
          http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0">
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <context-param>
        <param-name>contextClass</param-name>
        <param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
    </context-param>
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>aware.like.fox.crossing.water.AppConfig</param-value>
    </context-param>
</web-app>

Old black, mighty magic.

Why do we change from xml to java. Xml is for configuration, java is for intelligence. We changed for false reasons or both is true?

How do you add Java Based Spring config to an existing web.xml?

1 Answers1