Well, I'm trying to deploy a spring boot application in a tomcat 10 server, passing a one environment key. I need to pass de "secret" of jasypt for decode the passwords in my application, but I can't do this because the context don't run the same as the spring boot application normally.
In my App.java with main loos like
public class App extends SpringBootServletInitializer {
@Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
return application.sources(App.class);
}
public static void main(String[] args) throws Exception {
setProp();
final SpringApplication application = new SpringApplication(AppBatch.class);
application.run(args);
}
private static void setProp() throws Exception {
// Context ctx = new InitialContext();
// Context envCtx = (Context) ctx.lookup("java:comp/env");
// String propertyKey = (String) envCtx.lookup("jasypt.encriptor.password");
String propertyKey = System.getProperty("jasypt.encriptor.password");
Properties props = new Properties(System.getProperties());
if (propertyKey != null && !propertyKey.isEmpty()) {
props.setProperty("jasypt.encryptor.password", propertyKey);
System.setProperties(props);
} else {
throw new Exception("Not setted property in jasypt password");
}
}
}
This code works with an application runs in a normally deploy with Spring Boot, with the
java -jar -Djasypt.encryptor.password="secret" app.jar ...
The code commented is that I tried with tomcat but don't work, the application starts even before that this code, I can't see any log, even this log was in the method configure. But in the tomcat 10, this approach don't work. I need to pass this secret like a property or with the environment. How can I do?
