TL;DR All attributes are technically private. This design is a good one. You could just call a method in A from B. There are, of course, other options too.
Why doesn't BUILD see parent class attributes?
Quoting Wikipedia Fragile base class page problem:
One possible solution is to make instance variables private to their defining class and force subclasses to use accessors to modify superclass states.¹
Hence, per Raku Attributes doc:
In Raku, all attributes are private, which means they can be accessed directly only by the class instance itself.
B can call a method in A
This code looks natural:
class A { has $.name }
class B is A { submethod BUILD { $!name = 'foo' } }
Quoting again from Raku doc section linked above:
While there is no such thing as a public (or even protected) attribute, there is a way to have accessor methods generated automatically: replace the ! twigil with the . twigil (the . should remind you of a method call).
Your code generates a $!name attribute (private to A) plus a public .name method. Any code that uses the A class can call its public methods.
Your code hasn't used the autogenerated accessor method. But it could have done so with a couple small changes:
class A { has $.name is rw } # Add `is rw`
class B is A { submethod BUILD { self.name = 'foo' } } # s/$!name/self.name/²
say B.new # B.new(name => "foo")
is rw makes the public .name accessor method a read/write one instead of the default read only one.
Not using is rw
As I now understand from your first comment below, an is rw accessor is disallowed given your requirements. You can achieve any effect that a class supports via its public interface.
Let's first consider a silly example so it's clear you can do anything that any methods can do. Using, say, self.name, in A or B, might actually run one or more methods in A that make a cup of tea and return 'oolong' rather than doing anything with A's $!name:
class A {
has $.name = 'fred'; # Autogenerates a `method name` unless it's defined.
method name { 'oolong' } # Defines a `method name` (so it isn't generated).
}
my \a = A.new;
say a; # A.new(name => "fred")
say a.name; # oolong
Conversely, if an A object changes its $!name, doing so might have no effect whatsoever on the name of the next cup of tea:
class A {
has $.name = 'fred';
method name { 'rooibos' } # ignores `$!name`
method rename { $!name = 'jane' }
}
my \a = A.new;
say a; # A.new(name => "fred")
a.rename;
say a.name; # rooibos
To recap, you can (albeit indirectly) do anything with private state of a class that that class allows via its public API.
For your scenario, perhaps the following would work?:
class A {
has $.name;
multi method name { $!name }
multi method name (\val) { once $!name = val }
}
class B is A {
submethod BUILD { self.name: 42 }
}
my \a = B.new;
say a; # B.new(name => 42)
say a.name; # 42
a.name: 99; # Does nothing
say a.name; # 42
Footnotes
¹ Continuing to quote solutions listed by Wikipedia:
A language could also make it so that subclasses can control which inherited methods are exposed publicly.
Raku allows this.
Another alternative solution could be to have an interface instead of superclass.
Raku also supports this (via roles).
² self.name works where $!name does not. $.name throws a different compiler error with an LTA error message. See Using %.foo in places throws, but changing it to self.foo works.
