RequestDispatcher.include(...) appends servlet's package name

Question

I have an index.jsp page which uploads an image. On submit it goes to a servlet Upload.java. In the servlet I am checking if the extension in of image("jpg","png",etc) and forwards to new jsp page else it shows an error message and includes the same index.jsp page.

My servlet is a package named "servlets".

If I select an image then it is working properly. But if I select any file other than image then it shows the error with the index.jsp page as intended. Till now it works fine but if I upload any file even image from here, the server complains.

Here is how I am including the index.jsp page in UploadServlet.java servlet.

out.println("This type of file is not allowed. Please select an image.");
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/index.jsp");
dispatcher.include(request, response);

Here is the error from the server when I try to upload the image second time.

HTTP Status 404 - /UploadImage/servlets/servlets/UploadServlet

type Status report

message /UploadImage/servlets/servlets/UploadServlet

description The requested resource (/CropImage/servlets/servlets/UploadServlet) is not available.

Apache Tomcat/6.0.13

It is appending the servlet's package name to the url.

How to solve this problem?

Manohar, this is not true. It should have the same problem. It's just your misinterpretation of the problem. — BalusC, Sep 09 '11 at 14:54
I checked it in firefox and it worked fine I don't know how. But in IE it is giving problem. I will try your answer given below and let you all know. Thanks for your reply. — Manohar Bhattarai, Sep 09 '11 at 15:43

score 1 · Accepted Answer · answered Sep 09 '11 at 14:52

Apparently you're using a relative action URL in your <form>.

<form action="servlets/UploadServlet" ...>

When you open index.jsp, the request URL is

http://localhost:8080/UploadImage/index.jsp

When you submit the form, the action URL is relative to the current folder, so request URL will be

http://localhost:8080/UploadImage/servlets/UploadServlet

When you submit the form once again, the will be still relative to current folder, so you end up in

http://localhost:8080/UploadImage/servlets/servlets/UploadServlet

You need to fix it to be a domain-relative URL, starting with a leading slash.

<form action="/UploadImage/servlets/UploadServlet" ...>

This way the URL will be resolved relative to the domain root. You can also resolve the context path dynamically by ${pageContext.request.contextPath}:

<form action="${pageContext.request.contextPath}/servlets/UploadServlet" ...>

Thanks BalusC your answer solved my problem. I used
and the problem got solved. — Manohar Bhattarai, Sep 10 '11 at 04:08
You're welcome. I'd however suggest you to take benefit of the `doGet()` method of the servlet so that you end up with cleaner URLs. See also our servlets wiki page: http://stackoverflow.com/tags/servlets/info — BalusC, Sep 10 '11 at 04:17

score 0 · Answer 2 · edited Sep 09 '11 at 05:50

0

Your url is wrong. You can open the web.xml and find the "servlet-mapping" element there you can find the mapping url.

I guess your url may be "/CropImage/servlets/UploadServlet" .you can try to delete one "servlets" in the url.

edited Sep 09 '11 at 05:50

KV Prajapati

93,659
19
148
186

answered Sep 09 '11 at 05:30

ouotuo

64
3

This is the description of my J2EE component This is the display name of my J2EE component UploadServlet servlets.UploadServlet UploadServlet /servlets/UploadServlet – Manohar Bhattarai Sep 09 '11 at 08:44

RequestDispatcher.include(...) appends servlet's package name

2 Answers2