compare string key with object and return value

Asked Sep 01 '22 at 13:00

Active Sep 01 '22 at 13:00

Viewed 28 times

I have this function to check and return the value if key is equal to object key.

for example key is code and object have {'code':'123', 'name':'mokee'}, so in this case function should return 123. But below code condition is working but return always null.

 hasSameProps( prop, obj ) {
        let keys = Object.keys( obj )
         keys.forEach(function(key){
          if(key===prop){
            return obj[key];
          }
         });
        return null;
      }

asked Sep 01 '22 at 13:00

boycod3

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1

You can use `obj[prop]` to have "prop" evaluated and the result used as a key. – Pointy Sep 01 '22 at 13:03
3

rather than looping though all props you could do `return typeof obj[prop] !== 'undefined' ? obj[prop] : null` – Lawrence Cherone Sep 01 '22 at 13:04
2

Maybe I misunderstand your question, but doesn't `obj[prop]` achieve what you are trying to do? – PiFanatic Sep 01 '22 at 13:04
1

@LawrenceCherone your pieve of code will fail for falsey values, like `0`, `""`, `NaN` etc. Rather than using `||` you should use `??` – Krzysztof Krzeszewski Sep 01 '22 at 13:04
this is not working – boycod3 Sep 01 '22 at 16:56

compare string key with object and return value

0 Answers0