Dynamically generating input field

Question

<? $fileUpload=3 ; for($i=0;i<$fileUpload;$i++) { ?>
    <input type="file" name="upload_file" value="" id=" " />
<? } ?>

I want to actually generate three file upload field based on the loop, but this code is not working.

Actual requirement

On the click of the browse button, if the file is selected... the next field of form should appear... automatically and so on.

Really? why a loop? 3 iteration and no variable used inside, you better copy/paste 2 times... — JohnJohnGa, Sep 06 '11 at 20:14

score 1 · Accepted Answer · edited May 23 '17 at 12:19

1

<?php $fileUpload=3 ; for($i=0;$i<$fileUpload;$i++) { ?>
    <input type="file" name="upload_file" value="" id=" " />
<?php } ?>

You needed to change "i" to "$i" in your break condition.

Also don't get into the habit of short PHP opening tags: Link

edited May 23 '17 at 12:19

Community

answered Sep 06 '11 at 20:13

Gunnar Hoffman

1 Answers1