How to create a dummy variable of type folly::Future?

Question

So in the below code it can be observed that based on the Boolean variable flag. In the folly::collect operation we add or skip doing the std::move(cleanupFuture) operation.

Looking a way to avoid redundant code piece of the folly::collect?

I was thinking of using folly::Unit but not sure how it would be compatible as return type of cleanupFuture is a folly::Future<bool>

Logic:

  if (flag) {
    return folly::collect(
              std::move(abortFuture))
        .via(folly::CPUExecutor().get())
        .thenValue([](auto&& /* unused */) {});
  }

  return folly::collect(
             std::move(cleanupFuture),
             std::move(abortFuture))
      .via(folly::getGlobalCPUExecutor().get())
      .thenValue([](auto&& /* unused */) {});

Answer 1

flag ? std::move(cleanupFuture) : folly::makeFuture(true)