Unreachable code

Question

public void onClick(View v) {
    String uname=tv1.getText().toString();
    String pass=tv2.getText().toString();
    //String copmare=uname.concat(pass);

    Cursor cur = db.query("accountTable",    // Where are we looking?
        new String[]{ "colProject" },    // What do we want back?
        "colName = ? AND colPass = ?",   // What are we matching?
        new String[]{ uname, pass },     // What to put in the "holes"?
        null, null, null);               // Everything else default...

    if (cur != null) {
        cur.moveToNext();
    }
    return;

    Intent i = new Intent(FirstAssignmentActivity.this,success.class);
    i.putExtra("v1",   cur.getString(0));
    startActivity(i);

}

Why do I have unreachable code?

I downvoted you for not including error messages, low effort formatting, a lack of detailed description of both code and problem and particularly a lack of documentation of what you tried to fix the problem and where you're stuck. — blkpingu, May 09 '18 at 06:31

score 2 · Answer 1 · answered Sep 05 '11 at 05:36

2

You write return ;, so control will exit the function at that point and not reach the final 3 lines of the function (Intent i, etc)

answered Sep 05 '11 at 05:36

thedayturns

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score 0 · Answer 2 · answered Sep 05 '11 at 05:38

0

You are returning from the method. None of the code after that will execute.

if (cur != null) {
    cur.moveToNext();
}
return;  // AFTER THIS NOTHING WILL EXECUTE

answered Sep 05 '11 at 05:38

Nico Huysamen

10,217
9
62
88

Unreachable code

2 Answers2