How to grep/parse in string with Ansible

Question

I have problem with ansible. I need get version of apache with ansible, and I'm using command "httpd -v" in /bin/ folder of apache. Now, I've got output looks like "Server version: Apache/2.4.48 (Win64) Apache Lounge VS16 Server built: May 18 2021 10:45:56". So, can you help me please? I tried to use "regex" and there was still error.

Is a [way to check for installed yum package/rpm version in Ansible](https://stackoverflow.com/a/54096739/6771046) helpful for you? — U880D, Jul 15 '22 at 10:44

score 1 · Answer 1 · answered Jul 15 '22 at 11:04

Register the result of the command

    - command: httpd -v
      register: result

gives, for example,

result.stdout: |-
  Server version: Apache/2.4.46 (FreeBSD)
  Server built:   unknown

This is actually a YAML dictionary. Let's keep it in a variable. For example,

apache: "{{ result.stdout|from_yaml }}"

gives

apache:
  Server built: unknown
  Server version: Apache/2.4.46 (FreeBSD)

Now, you can reference the attributes. For example,

apache['Server version']: Apache/2.4.46 (FreeBSD)

and split the version

apache_version: "{{ apache['Server version']|split(' ')|first|
                                             split('/')|last }}"

gives

apache_version: 2.4.46

^{Example of a complete playbook
- hosts: srv
vars:
apache: "{{ result.stdout|from_yaml }}"
apache_version: "{{ apache['Server version']|split(' ')|first|
split('/')|last }}"
tasks:
- command: httpd -v
register: result
- debug:
var: apache_version}

I have this code, but it isn't working? Do you help me, please? Screenshot of my code: https://ctrlv.cz/Q2MK — Dave, Jul 15 '22 at 12:40

score 0 · Answer 2 · answered Jul 15 '22 at 14:34

using regex_search:

---
- hosts: localhost
  tasks:

  - name: Run httpd command
    shell: httpd -v
    register: httpd_version

  - name: show the extracted output
    debug:
      msg: "{{ httpd_version.stdout |regex_search('Server version.*?/([^ ]+).*','\\1') }}"

How to grep/parse in string with Ansible

2 Answers2