Python: Access elements of a binary string as if there are no spaces between

Question

I have a list of couple like this ('01 0 00 0',key0), ('01 0 11 0',key1), ('01 0 11 1',key2) and I would like to pick the elements with only the third and fourth bit equal to 1. So for example in this case I'll get ('01 0 11 0',key1) and ('01 0 11 1',key2).

How can I pick the couple with these elements ?

what you have tried so far? – Harsha Biyani Jul 15 '22 at 07:44 — Harsha Biyani, Jul 15 '22 at 07:44

Kins · Accepted Answer · 2022-07-15T07:52:00.877

0

You can use a list comprehension:

l = [i for i in list_couples if i[0].split(" ")[2]=="11"]

If the spaces are not always the same:

l = [i for i in list_couples if i[0].replace(" ", "")[3:5]=="11"]

edited Jul 15 '22 at 07:52

answered Jul 15 '22 at 07:47

Kins

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will only work if the spaces pattern is always the same as in examples. – Julien Jul 15 '22 at 07:49

score 0 · Answer 2 · answered Jul 15 '22 at 07:50

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You can just use list comprenhension, like this:

tuples = [('01 0 00 0',key0), ('01 0 11 0',key1), ('01 0 11 1',key2)]

res = [(s, k) for (s, k) in tuples if s.split(' ')[2] == '11']

answered Jul 15 '22 at 07:50

Rodrigo Llanes

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Python: Access elements of a binary string as if there are no spaces between

2 Answers2