How to get media-id from Instagram URL

Question

how can I get the media-id of a instagram posting from the url?

For example I need the media-id for https://www.instagram.com/p/Cf4dPucLzW0/

Solutions that does not work anymore:

Oembed dont give media-id back
adding ?__a=1 to a link redirects me to the post itself

score 3 · Answer 1 · edited Jul 26 '22 at 23:59

3

Put the following at the end of the post: ?__a=1&__d=dis, e.g.:

https://www.instagram.com/p/Cf4dPucLzW0/?__a=1&__d=dis

edited Jul 26 '22 at 23:59

dbc

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answered Jul 26 '22 at 23:47

GloryLanskoy

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Only works a couple of times. Then you get redirected. – penguin_P Jul 27 '22 at 10:16
@penguin_P did you find any solution? – Mehmet Peker Jul 29 '22 at 23:38
@Mehmet Peker Not really. If you use `?__a=1&__d=dis´ instead of `?__a=1` you well get blocked slower. If you have good rotating residential proxies, you can crawl some data. But this will work only for small amounts of crawls. – penguin_P Aug 01 '22 at 06:29
What is the true way to solve this issue? Do you know it? – nasser Sep 01 '22 at 12:10
It is not possible to crawl instagram media – penguin_P Feb 01 '23 at 12:54

score 0 · Answer 2 · answered May 31 '23 at 08:22

you need to have pageid, access token and an short code (which can be extracted from the URL you have for eg if this is the url :https://www.instagram.com/reel/Cs12TgIv8Ns/. "Cs12TgIv8Ns" is the short code)

then you can use the page id to convert to instagram business id using the following url: url = Graph + endpoint + '?fields=' + instagram_business_account + '&access_token=' + Token
convert the short code to

    alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_'
    media_id = 0
    for letter in short_code:
        media_id = (media_id * 64) + alphabet.index(letter)
    IG_id_list.append(str(media_id))

then use the following url to get various metrics and media id https://graph.facebook.com/v11.0/{instagram_business_account_id}/media?fields=....&access_token=token

How to get media-id from Instagram URL

2 Answers2