from scipy.signal import find_peaks
a=[2,3,4,1]
b=find_peaks(a)
print(b)
I am getting the indices. But I want the values. How can I get the values of the list?
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2 Answers
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You can use the indices on the original vector to return the value of the peak like this:
a = np.array([2, 3, 4, 1])
peaks, properties = find_peaks(a)
a[peaks]
ethanknights
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The easiest way is to convert a to a numpy array then index it.
a = np.array([2, 3, 4, 1, 5, 0], dtype=np.float32)
idx, props = find_peaks(a)
val = a[idx]
print(idx) # this outputs [2 4]
print(val) # this outputs [4. 5.]
brentertainer
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My list doesn't contain integers. It is showing 'only integer scalar arrays can be converted to a scalar index' – Abhilipsa Jul 08 '22 at 17:34
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@Abhilipsa. So what? – Mad Physicist Jul 08 '22 at 17:35
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@MadPhysicist I'm unable to get the values – Abhilipsa Jul 08 '22 at 17:37
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That's not very informative – Mad Physicist Jul 08 '22 at 17:46
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@MadPhysicist The list should have only integers according to the error. But my list contains float values. – Abhilipsa Jul 08 '22 at 17:48
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@Abhilipsa Your comment indicates that you are trying to access `a` with invalid indices. Are you splitting the output of `find_peaks` into its parts like I did in my example? `find_peaks` returns a 2-tuple, and only the first element of the tuple contains the indices of the peaks. – brentertainer Jul 08 '22 at 17:55