Most recent file from a directory with Python

Question

import os
fish=os.listdir("H:\Comu\Solo")
print(fish)

The result is:['lamba_20081104.pdf', 'conal_20070918.pdf', 'apialas_20220628.pdf']

the result is a list of the three file in the directory and my wished final result is: 20220628

I am not able to proceed...

The characters of the file to be taken are from -12 to -4

The result represents the date of the younger file (28.06.2022) in the directory "H:\Comu\Solo", because the number are date! In contrast with Ruby - Get the second most recent file from a directory?, in my case is the name-code of the file that suggests me the date!

Someone can write the script to obtain 20220628?

thank you very much

Regex? `re.findall(r"\d+", file_name)` or `re.findall(r"(\d{4})(\d{2})(\d{2})", file_name)` — 001, Jun 28 '22 at 13:59

Mehrdad Pedramfar · Accepted Answer · 2022-06-28T14:01:42.160

3

Try this in one line:

max(fish, key=lambda x: x.split("_")[1].split(".")[0])

Python max accepts an argument(key) that will return your custom max function.

as @sniperd said,you can also use regex in the key:

max(l, key=lambda x: re.findall(r"\d+", x))

edited Jun 28 '22 at 14:01

answered Jun 28 '22 at 13:59

Mehrdad Pedramfar

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That's actually very clever! I was going regex route. – sniperd Jun 28 '22 at 14:01
@sniperd Thanks for the suggestion. I add it to my answer. – Mehrdad Pedramfar Jun 28 '22 at 14:02
@simone100 Your welcome. please check the gray button beside and turn it to green. – Mehrdad Pedramfar Jul 03 '22 at 10:46
is it right now? – simone100 Jul 03 '22 at 10:48

Most recent file from a directory with Python

1 Answers1