CRC divisor calculation

Question

Im trying to understand CRC and I'm getting confused as how to calculate the 'divisor'.

In the example on wikipedia the divisor is 11 (1011) for input of 11010011101100

11010011101100 000 <--- input left shifted by 3 bits
1011               <--- divisor (4 bits) = x³+x+1
------------------
01100011101100 000 <--- result

How is the divisor calculated? In this example (x³+x+1) x is 2? Where did the 2 come from?

The divisor in binary is just the coefficients of its polynomial. `x^3 + x + 1` equals `1*x^3 + 0*x^2 + 1*x +1*1`; read off the cofficients to get 1-0-1-1 — Nemo, Sep 01 '11 at 14:33

score 2 · Accepted Answer · answered Sep 01 '11 at 16:01

2

From the "Mathematics of CRC" section of that same wikipedia it starts "Mathematical analysis of this division-like process reveals how to pick a divisor that guarantees good error-detection properties." This is the key to it. Some divisors are better than others so you just find a standard one and use that usually.

The bottom of that page describes some of the different CRCs used and the polynomial that defines their divisors.

answered Sep 01 '11 at 16:01

Chris

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Given a `n` digit input data how does one find out the bits of the divisor? – Sabito stands with Ukraine Jan 18 '21 at 16:17

score 1 · Answer 2 · answered Sep 01 '11 at 14:29

1

It's written in the next sentence @wikipedia:

If the input bit above the leftmost divisor bit is 0, do nothing. If the input bit above the leftmost divisor bit is 1, the divisor is XORed into the input.

Which means:

1101 xor 1011 => 0110

answered Sep 01 '11 at 14:29

duedl0r

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score -3 · Answer 3 · edited Jan 18 '21 at 12:15

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The divisor in binary is just the coefficients of its polynomial. x^3 + x + 1 = 1x^3 + 0x^2 + 1x +11; read off the cofficients to get 1 0 1 1

edited Jan 18 '21 at 12:15

Sabito stands with Ukraine

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answered Mar 06 '14 at 08:50

user3387268

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CRC divisor calculation

3 Answers3