Converting an integer to Char Pointer using C

Question

I am trying to convert an integer to a char pointer as shown below. The data results are different. I am not sure what is going wrong. Please help me in correcting the code.

int main(){ 
    char *key1 = "/introduction";
    std::ostringstream str1;
    str1<< 10;   
    std::string data=str1.str();
    std::cout <<"The data value="<<data<<std::endl;  // The data value= 10
    char *intro= new char[data.length()+1];
    
    strcpy(intro, data.c_str());
    std::cout <<"The data value="<<*intro <<std::endl; // The data value=1
          
    return 0;
}

I am not sure why two data value are printed different i.e, 10 and 1.

It worked. Thank you @IłyaBursov for the great help. Please explain me the reason if possible. — Manu, Jun 13 '22 at 03:35
There are loads of unnecessary conversions there but oh well... — Havenard, Jun 13 '22 at 04:20

score 4 · Accepted Answer · answered Jun 13 '22 at 03:35

In C++, when trying to print all the contents of a char * with cout, you should pass the pointer, i.e. cout << intro << endl.

What you've done here is dereferenced the char *, so cout << *intro << endl is equivalent to cout << intro[0] << endl, which is equivalent to printing the first character, 1.

Converting an integer to Char Pointer using C

1 Answers1