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I want to experiment io_uring on the github project: https://github.com/alexhultman/io_uring_epoll_benchmark

referrence: https://unixism.net/loti/ref-liburing/completion.html

however I stumbled upon 2 functions:

  1. unsigned io_uring_peek_batch_cqe(struct io_uring *ring, struct io_uring_cqe **cqes, unsigned count)

  2. int io_uring_wait_cqe_nr(struct io_uring *ring, struct io_uring_cqe **cqe_ptr, unsigned wait_nr)

I understand that the first functions will fills in an array of I/O completions up to count to the cqes and will return regardless of how many cqes completions

However the second functions only fills in one I/O completions to the cqes even I wait for wait_nr completions, why is this so, if it wait for specific number of cqes completions, why i didn't fill in the array of I/O like the first function did?

like example i create: #define MAX_BATCH 2000

struct io_uring_cqe **cqes = malloc(sizeof(struct io_uring_cqe *) * MAX_BATCH);

if I run on the first function, i could access cqes[i] i = (0 to completions)

if I run on the second function, I can only access cqes[i] i = 0

I need to understand why the second function never update the array of cqes like the first function did

QuickQuail
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1 Answers1

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I've solved it, As the second function:

int io_uring_wait_cqe_nr(struct io_uring *ring, struct io_uring_cqe **cqe_ptr, unsigned wait_nr)

will wait until for wait_nr completions cqe to complete before moving on, and it will return cqe I/O completions and update only the first array of cqes, which is cqes[0],

But for the first function:

unsigned io_uring_peek_batch_cqe(struct io_uring *ring, struct io_uring_cqe **cqes, unsigned count)

will return regardless whether or not theres a cqe, and will return the numbers of cqes and the array of cqes I/O

After checking the struct of cqes whether the asynchronous was done properly, mark it with the function:

void io_uring_cq_advance(struct io_uring *ring, struct io_uring_cqe *cqe, unsigned count) to free up the cqes entries so the next cqes will point to cqes[0]

QuickQuail
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