beginner c++: virtual functions in a base class

Question

I'm writing some code where I defined the following base class.

class Chorus{
  public:

    //Destructor
    virtual ~Chorus();

    //callback function
    virtual int callback( void *outputBuffer, void *notUsed, unsigned int 
       nBufferFrames, double streamTime, RtAudioStreamStatus status, void *userData );

    virtual void initializeDelayBuffer(void);

    virtual void destroyDelayBuffer(void);
};

I want to use this as a base class and not actually do anything with it on its own. So I have two seperate classes which are derived from this class Chorus. I wanted to do this to simply provide some basic constraints as to what any derived Chorus class MUST have to be considered usable in my program.

When I build my project (Visual Studio 2008), I get unresolved external symbol errors on all the virtual functions from this Chorus class. I'm guessing it's the typical error where I didn't make forward declarations of these functions. But, since they are virtual and I don't want them to actually be defined to do anything until they are defined within the deriving classes, what do I do to resolve this issue?

score 15 · Accepted Answer · answered Apr 06 '09 at 19:37

If your intent is for them to be simply place holders for child classes to implement, then make them pure virtual functions by ending with = 0. For example

virtual void destroyDelayBuffer(void) = 0;

This makes the method "abstract" so to speak. The C++ compiler will not look for an actual definition of the method but instead will force all derived classes to implement these methods before an instance can be created.

score 3 · Answer 2 · answered Apr 06 '09 at 19:38

3

You need to declare those function as pure virtual.

virtual void initializeDelayBuffer(void) = 0;

That will create an interface of sorts, which is what you want.

answered Apr 06 '09 at 19:38

MattJ

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Agree, but please remove the void from the argument list; that's C not C++. – Brian Neal Apr 06 '09 at 19:44

score 2 · Answer 3 · answered Apr 06 '09 at 19:39

2

This is called a pure virtual function. In C++ you write a "=0" after the function name, but you probably want to read the FAQ on these.

http://www.parashift.com/c++-faq-lite/abcs.html#faq-22.4

answered Apr 06 '09 at 19:39

Uri

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score 2 · Answer 4 · answered Apr 06 '09 at 19:39

2

You need to define the functions as pure virtual functions. To do this, add a " = 0" after each declaration. For example:

virtual void destroyDelayBuffer(void) = 0;

answered Apr 06 '09 at 19:39

Jon Benedicto

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score 1 · Answer 5 · answered Apr 06 '09 at 19:37

1

Use a pure virtual function:

  virtual int callback( void *outputBuffer, void *notUsed, unsigned int 
       nBufferFrames, double streamTime, RtAudioStreamStatus status, void *userData ) = 0;

answered Apr 06 '09 at 19:37

Pablo Santa Cruz

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score 1 · Answer 6 · answered Apr 07 '09 at 05:26

1

Just to add to the above answers, you cannot instantiate an object of a class containing pure virtual functions, so in the future if you intend to have objects of your base class, do remember to make the function non-pure virtual.

answered Apr 07 '09 at 05:26

Shree

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Yea, it's a base class to only be derived from. There will never be objects of it because it is too skeletal to do anything useful. – Rich Apr 10 '09 at 19:41

beginner c++: virtual functions in a base class

6 Answers6