SchemDraw returns blank schematic when using logicparse

Question

Python 3.8, Spyder IDE

I installed Schemdraw using,

pip install schemdraw[matplotlib]

I'm using the following code but all I get is a blank canvas,

import schemdraw
import schemdraw.elements as elm
from schemdraw import logic
from schemdraw.parsing import logicparse

with schemdraw.Drawing() as d:
    logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$')

Also tried,

with schemdraw.Drawing() as d:
    d = logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$')
    d.draw()

Gives a blank canvas.

Also tried,

with schemdraw.Drawing() as d:
    d.add(logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$'))

Also tried,

d = logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$')
d.draw()

Returns nothing not even a blank canvas.

This throws the following error,

Traceback (most recent call last):

  File "D:\Python codes\temp.py", line 10, in <module>
    d.add(logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$'))

  File "D:\ProgramData\Anaconda3\lib\site-packages\schemdraw\schemdraw.py", line 233, in add
    element = element(**kwargs)

TypeError: 'Drawing' object is not callable

I have also tried (after the imports) just,

logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$')

which gives no output at all. I have the lastest version of pyparse installed.

Whereas the following simple circuit works fine,

with schemdraw.Drawing() as d:
    d.add(elm.Resistor())
    d.add(elm.Capacitor())
    d.add(elm.Diode())

Is there something obvious missing here?

Can you please show the full traceback for the "Drawing is not callable" error? — mkrieger1, May 11 '22 at 08:39

score 1 · Answer 1 · answered May 11 '22 at 18:46

1

Try this:

from schemdraw.parsing import logicparse

drawing = logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$')
drawing.draw()

answered May 11 '22 at 18:46

MatLag

11
1

I have tried that & it returns nothing, not even a blank canvas – DrBwts May 12 '22 at 12:14

score 1 · Accepted Answer · answered May 18 '22 at 03:32

You could try:

with logicparse('not ((w and x) or (y and z))', outlabel='$\overline{Q}$'):
    pass

logicparse returns a Drawing, so it doesn't work to put it inside a with schemdraw.Drawing block. But somehow Spyder's console doesn't seem to pick up the Figure from Drawing.draw().

SchemDraw returns blank schematic when using logicparse

2 Answers2